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Given 2.0 grams of Fe and 3.5 grams of oxygen gas, how many moles of iron (III) oxide can be made in the following unbalanced reaction? (NOTE: Be sure to balance it firsty)
Fe + 02
FezO:
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Transcript
To determine the amount of iron 3 oxide that can be made from 2 gas iron and 3.5 grams oxygen will first balance the chemical reaction. We’Ve got 2 moles iron, 3 moles oxygen, 2 moles oxygen, 1 mole iron, so we need to get an even number of oxygen. So if we multiply this by 2, that will give us 6 moles of oxygen. We can then multiply this by 3 to get 6 moles oxygen, but that introduced 4 moles iron. So we need to put a 4 here. If we start with 2 grams of iron, we can divide by the molar massive iron to get moles iron. Then 4 moles iron yield 2 moles iron, 3 oxide, and if we want, we can multiply by the molar mass in order to get grams, iron, 3 oxide will do a similar calculation with…
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