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Speed is how fast an object moves in a certain direction. Mathematically, speed is often seen as the change in position of an object over time. This basic concept is present in many physics problems. Which formula should be used depends on what is known of the object, to choose the right formula, read this article carefully.
- Average speed = vav=xf−xitf−ti{displaystyle v_{av}={frac {x_{f}-x_{i}}{t_{f}-t_{i}}}}
- xf={displaystyle x_{f}=} last place xi={displaystyle x_{i}=} original location
- tf={displaystyle t_{f}=} last time ti={displaystyle t_{i}=} initial time
- Average velocity when acceleration is constant = vav=vi+vf2{displaystyle v_{av}={frac {v_{i}+v_{f}}{2}}}
- vi={displaystyle v_{i}=} initial velocity vf={displaystyle v_{f}=} Last velocity
- Average velocity if acceleration is constant equal to 0 = vav=xt{displaystyle v_{av}={frac {x}{t}}}
- Final velocity =vf=vi+at{displaystyle v_{f}=v_{i}+at}
- a = acceleration t = time
Steps
Find Average Velocity
- For example, consider a train with a constant acceleration from 30 m/s to 80 m/s. So the average speed of the train is 30+802=55m/S{displaystyle {frac {30+80}{2}}=55m/s} .
- The formula in this case is vav=xf−xitf−ti{displaystyle v_{av}={frac {x_{f}-x_{i}}{t_{f}-t_{i}}}} , i.e. “end position – initial position divided by end time – initial time”. You can also rewrite this formula as vav{displaystyle v_{av}} = Δx / Δt , or “change of position over time”.
- Example 1 : A car traveling east starts at position x = 5 meters. After 8 seconds, the car is at position x = 41 meters. How far has the car moved?
- The car has moved (41m-5m) = 36 meters east.
- Example 2 : A diver jumps 1 meter above the jump board, then falls 5 meters before hitting the water. How much has the athlete moved?
- In total, the diver has moved 4 meters below the original position, that is, 4 meters below, or -4 meters in other words. (0 + 1 – 5 = -4). Although the total distance traveled is 6 meters (1 meter up when jumping and 5 meters when falling), the problem lies in the fact that the end of the movement is 4 meters below the starting position.
- Example 1 (continued): The problem says that the car takes 8 seconds to get from the starting point to the end, so this is the change in time.
- Example 2 (continued): If the athlete jumps at t = 7 seconds and re-waters at t = 8 seconds, change in time = 8 seconds – 7 seconds = 1 second.
- Example 1 (continued): The car traveled a distance of 36 meters in 8 seconds. We have vav=36m8S={displaystyle v_{av}={frac {36m}{8s}}=} 4.5 m/s to the east.
- Example 2 (continued): The athlete traveled a distance of -4 meters in 1 second. We have vav=−4mfirstS={displaystyle v_{av}={frac {-4m}{1s}}=} -4 m/s . (In one-way motion, a negative number usually implies “downward” or “to the left. In this example, we could give the answer “4 m/s in the downward direction”).
- Example 3 : A person walks 3 meters east, then turns 90 degrees and walks another 4 meters north. How much has this person moved?
- Draw a graph and connect the start point to the end point in a straight line. We have a right triangle, using the property of right triangles we will calculate the length of its side. In this example, the distance traveled is 5 meters northeast.
- Sometimes the teacher may ask you to find the exact direction of travel (the angle above the horizontal). You can use geometric properties or draw vectors to solve that problem. [2] X Research Source
Finding Velocity knowing Acceleration
- vf=vi+at{displaystyle v_{f}=v_{i}+at} , or “final velocity = initial velocity + (acceleration* time)”
- Initial velocity vi{displaystyle v_{i}} sometimes written as v0{displaystyle v_{0}} (“velocity at time t = 0”).
- Example : A train is traveling north with a speed of 2 m/s and an acceleration of 10 m/s 2 . How much will the train’s speed increase in the next 5 seconds?
- a = 10 m/s 2
- t = 5 seconds
- Increased velocity (a * t) = (10 m/s 2 * 5 s) = 50 m/s.
- Example (continued) : In this example, what is the speed of the train after 5 seconds?
- vf=vi+at{displaystyle v_{f}=v_{i}+at}
- vi=2m/S{displaystyle v_{i}=2m/s}
- at=50m/S{displaystyle at=50m/s}
- vf=2m/S+50m/S=52m/S{displaystyle v_{f}=2m/s+50m/s=52m/s}
- In the example above, since the train is always moving north and doesn’t change direction all the time, its speed is 52 m/s north.
Circular Motion Velocity
- The circular motion of an object is calculated by dividing the circumference of the orbit by the time of motion.
- The calculation formula is as follows:
- v = (2πr) / T
- Note: 2πr is the circumference of the motion’s trajectory
- r is “radius”
- T is “motion time interval”
- For example, calculate the speed of circular motion of an object with a radius of 8 meters in 45 seconds.
- r = 8 m
- T = 45 seconds
- Perimeter = 2πr = ~ (2)(3.14)(8 m) = 50.24 m
- Example: v = (2πr) / T = 50.24 m / 45 s = 1.12 m/s
- The speed of the circular motion of the object is 1.12 m/s.
Advice
- Meters per second (m/s) is the standard unit of speed. Double check that the distance is in meters and that the time is in seconds, for acceleration the standard unit is meters per second per second (m/s 2 ).
This article is co-authored by a team of editors and trained researchers who confirm the accuracy and completeness of the article.
The wikiHow Content Management team carefully monitors the work of editors to ensure that every article is up to a high standard of quality.
This article has been viewed 38,834 times.
Speed is how fast an object moves in a certain direction. Mathematically, speed is often seen as the change in position of an object over time. This basic concept is present in many physics problems. Which formula should be used depends on what is known of the object, to choose the right formula, read this article carefully.
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